2y/4y^2=6

Solution for 2y/4y^2=6 equation:

2y/4y^2=6

We move all terms to the left:

2y/4y^2-(6)=0


Domain of the equation: 4y^2!=0

y^2!=0/4

y^2!=√0

y!=0

y∈R


We multiply all the terms by the denominator


2y-6*4y^2=0

Wy multiply elements

-24y^2+2y=0

a = -24; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-24)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-24}=\frac{-4}{-48}
=1/12
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-24}=\frac{0}{-48}
=0
$